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MATH SOLVE
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Given that sec 0= -37/12, what is the value of cot 0, for pi/2 < 0 pi?
4 months ago
Q:
Given that sec 0= -37/12, what is the value of cot 0, for pi/2 < 0 pi?
Accepted Solution
A:
Answer: cot(θ) = -12/35Step-by-step explanation: cot(θ) = -1/√(sec(θ)^2 -1) . . . . negative in the second quadrant = -1/√((-37/12)^2 -1) = -1/(35/12) cot(θ) = -12/35